Is this correct?

[Jd_]

Yes
..............

I just use I = V/R (Current equals voltage divided by resistance)

4.20volts divided by 0.10ohm equals 42amps, x by the voltage equals 176.4 watts.

8.40volts divided by 0.40ohm equals 21amps, x by the voltage equals 176.4 watts.

You would/ should know your voltage and coil resistance, I see no reason to further complicate matters?

Spirit of enquiry?

Or in @Jd_ 's case... Inquiry?

I was trying to leave the amps out of those 2 equations because i was having trouble understanding how the coils resistance determines how many volts are equal to how many watts

Voltage squared divided by resistance equals wattage

Square root of wattage multipied by resistance equals voltage

 

[Jd_]

In my head now i understand that concept

I already understood the concept of
Wattage divided by voltage equals amp load

Im only up to the 3 variables at a time, not 4 (or 2 variables and a constant). In other words 3 letters at a time not 4 letters

Baby steps, ya know

Edit: i want to understand

 

[OzoreXS]

Sorry mate. I have no clue of what your talking about
and I don't want to know either lol